[jQuery] ajax 콜백함수에서 파라메터 패싱 :

Pass variable to function in jquery AJAX success callback

[QUESTION] 질문

I am trying to preload some images with a jQuery AJAX call, but am having real problems passing a (url) string into a function within the success function of the AJAX call (if that makes sense).

Here is my code as is stands:

//preloader for images on gallery pages
window.onload = function() {
    setTimeout(function() {     
        var urls = ["./img/party/"]; //just one to get started

        for ( var i = 0; i < urls.length; i++ ) {
            $.ajax({
                url: urls[i],
                success: function(data,url) {
                    $(data).find("a:contains(.jpg)").each(function(url) {                               
                        new Image().src = url + $(this).attr("href");
                    });
                }
            });
        };  
    }, 1000);
};

One can see my (failed) attempt at passing the url through into the .each() call - url ends up takes the value of increasing integers. Not sure why or what these relate to, maybe the number of jpg files?

...anyway, it should of course take the single value in my original urls array.

Thanks for any help - I always seem to get in a bit of a twist with these callbacks.

 

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[ANSWER] 답변

I was just experiencing a similar issue, and believe I have found a solution.

Since the settings object is tied to that ajax call, you can simply add in the indexer as a custom setting, which you can then access using this in the success callback:

//preloader for images on gallery pages
window.onload = function() {
    var urls = ["./img/party/","./img/wedding/","./img/wedding/tree/"];

    setTimeout(function() {
        for ( var i = 0; i < urls.length; i++ ) {
            $.ajax({
                url: urls[i],
                indexValue: i,
                success: function(data) {
                    image_link(data , this.indexValue);

                    function image_link(data, i) {
                        $(data).find("a:contains(.jpg)").each(function(){ 
                            console.log(i);
                            new Image().src = urls[i] + $(this).attr("href");
                        });
                    }
                }
            });
        };  
    }, 1000);       
};

Hopefully that does the trick.

 

[출처] https://stackoverflow.com/questions/18413969/pass-variable-to-function-in-jquery-ajax-success-callback

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